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306n^2-90n=0
a = 306; b = -90; c = 0;
Δ = b2-4ac
Δ = -902-4·306·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-90}{2*306}=\frac{0}{612} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+90}{2*306}=\frac{180}{612} =5/17 $
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